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6(x-5)=2(3x+2)+26
We move all terms to the left:
6(x-5)-(2(3x+2)+26)=0
We multiply parentheses
6x-(2(3x+2)+26)-30=0
We calculate terms in parentheses: -(2(3x+2)+26), so:We get rid of parentheses
2(3x+2)+26
We multiply parentheses
6x+4+26
We add all the numbers together, and all the variables
6x+30
Back to the equation:
-(6x+30)
6x-6x-30-30=0
We add all the numbers together, and all the variables
-60!=0
There is no solution for this equation
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