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6(x-5)+9x=47+4x
We move all terms to the left:
6(x-5)+9x-(47+4x)=0
We add all the numbers together, and all the variables
6(x-5)+9x-(4x+47)=0
We add all the numbers together, and all the variables
9x+6(x-5)-(4x+47)=0
We multiply parentheses
9x+6x-(4x+47)-30=0
We get rid of parentheses
9x+6x-4x-47-30=0
We add all the numbers together, and all the variables
11x-77=0
We move all terms containing x to the left, all other terms to the right
11x=77
x=77/11
x=7
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