6(x-5)+2=8(2x-5)+22

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Solution for 6(x-5)+2=8(2x-5)+22 equation: 



6(x-5)+2=8(2x-5)+22

We move all terms to the left:

6(x-5)+2-(8(2x-5)+22)=0

We multiply parentheses

6x-(8(2x-5)+22)-30+2=0



We calculate terms in parentheses: -(8(2x-5)+22), so:

8(2x-5)+22

We multiply parentheses

16x-40+22

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We add all the numbers together, and all the variables

6x-(16x-18)-28=0

We get rid of parentheses

6x-16x+18-28=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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