6(x-4)=2(4+x)

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Solution for 6(x-4)=2(4+x) equation:



6(x-4)=2(4+x)
We move all terms to the left:
6(x-4)-(2(4+x))=0
We add all the numbers together, and all the variables
6(x-4)-(2(x+4))=0
We multiply parentheses
6x-(2(x+4))-24=0
We calculate terms in parentheses: -(2(x+4)), so:
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
We get rid of parentheses
6x-2x-8-24=0
We add all the numbers together, and all the variables
4x-32=0
We move all terms containing x to the left, all other terms to the right
4x=32
x=32/4
x=8

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