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6(x-4)/3=4(x+1)/12
We move all terms to the left:
6(x-4)/3-(4(x+1)/12)=0
We calculate fractions
6x/()+(-(4(x+1)*3)/()=0
We calculate terms in parentheses: +(-(4(x+1)*3)/(), so:We get rid of parentheses
-(4(x+1)*3)/(
We multiply all the terms by the denominator
-(4(x+1)*3)
We calculate terms in parentheses: -(4(x+1)*3), so:We get rid of parentheses
4(x+1)*3
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
-12x-12
Back to the equation:
+(-12x-12)
6x/()-12x-12=0
We multiply all the terms by the denominator
6x-12x*()-12*()=0
We add all the numbers together, and all the variables
6x-12x*()=0
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