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6(x-3)=2(x-5)
We move all terms to the left:
6(x-3)-(2(x-5))=0
We multiply parentheses
6x-(2(x-5))-18=0
We calculate terms in parentheses: -(2(x-5)), so:We get rid of parentheses
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
6x-2x+10-18=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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