6(x-3)=11-2(2-x)

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Solution for 6(x-3)=11-2(2-x) equation: 



6(x-3)=11-2(2-x)

We move all terms to the left:

6(x-3)-(11-2(2-x))=0

We add all the numbers together, and all the variables

6(x-3)-(11-2(-1x+2))=0

We multiply parentheses

6x-(11-2(-1x+2))-18=0



We calculate terms in parentheses: -(11-2(-1x+2)), so:

11-2(-1x+2)

determiningTheFunctionDomain
-2(-1x+2)+11

We multiply parentheses

2x-4+11

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We get rid of parentheses

6x-2x-7-18=0

We add all the numbers together, and all the variables

4x-25=0

We move all terms containing x to the left, all other terms to the right

4x=25

x=25/4

x=6+1/4

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