6(x-3)/4=6(x+1)/12

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Solution for 6(x-3)/4=6(x+1)/12 equation: 



6(x-3)/4=6(x+1)/12

We move all terms to the left:

6(x-3)/4-(6(x+1)/12)=0

We calculate fractions


6x/()+(-(6(x+1)*4)/()=0



We calculate terms in parentheses: +(-(6(x+1)*4)/(), so:

-(6(x+1)*4)/(

We multiply all the terms by the denominator


-(6(x+1)*4)



We calculate terms in parentheses: -(6(x+1)*4), so:

6(x+1)*4

We multiply parentheses

24x+24

Back to the equation:

-(24x+24)



We get rid of parentheses

-24x-24

Back to the equation:

+(-24x-24)



We get rid of parentheses

6x/()-24x-24=0

We multiply all the terms by the denominator


6x-24x*()-24*()=0

We add all the numbers together, and all the variables

6x-24x*()=0

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