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6(x-3)/3=2(x+5)/9
We move all terms to the left:
6(x-3)/3-(2(x+5)/9)=0
We calculate fractions
6x/()+(-(2(x+5)*3)/()=0
We calculate terms in parentheses: +(-(2(x+5)*3)/(), so:We get rid of parentheses
-(2(x+5)*3)/(
We multiply all the terms by the denominator
-(2(x+5)*3)
We calculate terms in parentheses: -(2(x+5)*3), so:We get rid of parentheses
2(x+5)*3
We multiply parentheses
6x+30
Back to the equation:
-(6x+30)
-6x-30
Back to the equation:
+(-6x-30)
6x/()-6x-30=0
We multiply all the terms by the denominator
6x-6x*()-30*()=0
We add all the numbers together, and all the variables
6x-6x*()=0
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