6(x-3)/2=3(x+9)/13

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Solution for 6(x-3)/2=3(x+9)/13 equation: 



6(x-3)/2=3(x+9)/13

We move all terms to the left:

6(x-3)/2-(3(x+9)/13)=0

We calculate fractions


6x/()+(-(3(x+9)*2)/()=0



We calculate terms in parentheses: +(-(3(x+9)*2)/(), so:

-(3(x+9)*2)/(

We multiply all the terms by the denominator


-(3(x+9)*2)



We calculate terms in parentheses: -(3(x+9)*2), so:

3(x+9)*2

We multiply parentheses

6x+54

Back to the equation:

-(6x+54)



We get rid of parentheses

-6x-54

Back to the equation:

+(-6x-54)



We get rid of parentheses

6x/()-6x-54=0

We multiply all the terms by the denominator


6x-6x*()-54*()=0

We add all the numbers together, and all the variables

6x-6x*()=0

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