6(x-3)-4(x-2)=12

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Solution for 6(x-3)-4(x-2)=12 equation:



6(x-3)-4(x-2)=12
We move all terms to the left:
6(x-3)-4(x-2)-(12)=0
We multiply parentheses
6x-4x-18+8-12=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11

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