6(x-3)-10=2(x+3)

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Solution for 6(x-3)-10=2(x+3) equation: 



6(x-3)-10=2(x+3)

We move all terms to the left:

6(x-3)-10-(2(x+3))=0

We multiply parentheses

6x-(2(x+3))-18-10=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

6x-(2x+6)-28=0

We get rid of parentheses

6x-2x-6-28=0

We add all the numbers together, and all the variables

4x-34=0

We move all terms containing x to the left, all other terms to the right

4x=34

x=34/4

x=8+1/2

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