6(x-3)+10=2(4x-4)

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Solution for 6(x-3)+10=2(4x-4) equation: 



6(x-3)+10=2(4x-4)

We move all terms to the left:

6(x-3)+10-(2(4x-4))=0

We multiply parentheses

6x-(2(4x-4))-18+10=0



We calculate terms in parentheses: -(2(4x-4)), so:

2(4x-4)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

6x-(8x-8)-8=0

We get rid of parentheses

6x-8x+8-8=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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