6(x-3)+10=2(3y-4)

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Solution for 6(x-3)+10=2(3y-4) equation:


Simplifying
6(x + -3) + 10 = 2(3y + -4)

Reorder the terms:
6(-3 + x) + 10 = 2(3y + -4)
(-3 * 6 + x * 6) + 10 = 2(3y + -4)
(-18 + 6x) + 10 = 2(3y + -4)

Reorder the terms:
-18 + 10 + 6x = 2(3y + -4)

Combine like terms: -18 + 10 = -8
-8 + 6x = 2(3y + -4)

Reorder the terms:
-8 + 6x = 2(-4 + 3y)
-8 + 6x = (-4 * 2 + 3y * 2)
-8 + 6x = (-8 + 6y)

Add '8' to each side of the equation.
-8 + 8 + 6x = -8 + 8 + 6y

Combine like terms: -8 + 8 = 0
0 + 6x = -8 + 8 + 6y
6x = -8 + 8 + 6y

Combine like terms: -8 + 8 = 0
6x = 0 + 6y
6x = 6y

Solving
6x = 6y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = y

Simplifying
x = y

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