6(x-2)=8x+8(3x+5)

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Solution for 6(x-2)=8x+8(3x+5) equation:



6(x-2)=8x+8(3x+5)
We move all terms to the left:
6(x-2)-(8x+8(3x+5))=0
We multiply parentheses
6x-(8x+8(3x+5))-12=0
We calculate terms in parentheses: -(8x+8(3x+5)), so:
8x+8(3x+5)
We multiply parentheses
8x+24x+40
We add all the numbers together, and all the variables
32x+40
Back to the equation:
-(32x+40)
We get rid of parentheses
6x-32x-40-12=0
We add all the numbers together, and all the variables
-26x-52=0
We move all terms containing x to the left, all other terms to the right
-26x=52
x=52/-26
x=-2

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