6(x-2)=4(x-4)+6

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Solution for 6(x-2)=4(x-4)+6 equation: 



6(x-2)=4(x-4)+6

We move all terms to the left:

6(x-2)-(4(x-4)+6)=0

We multiply parentheses

6x-(4(x-4)+6)-12=0



We calculate terms in parentheses: -(4(x-4)+6), so:

4(x-4)+6

We multiply parentheses

4x-16+6

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We get rid of parentheses

6x-4x+10-12=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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