6(x-2)=4(x-3)+2x

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Solution for 6(x-2)=4(x-3)+2x equation: 



6(x-2)=4(x-3)+2x

We move all terms to the left:

6(x-2)-(4(x-3)+2x)=0

We multiply parentheses

6x-(4(x-3)+2x)-12=0



We calculate terms in parentheses: -(4(x-3)+2x), so:

4(x-3)+2x

We add all the numbers together, and all the variables

2x+4(x-3)

We multiply parentheses

2x+4x-12

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

6x-6x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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