6(x-2)=3(x-4)+3x

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Solution for 6(x-2)=3(x-4)+3x equation: 



6(x-2)=3(x-4)+3x

We move all terms to the left:

6(x-2)-(3(x-4)+3x)=0

We multiply parentheses

6x-(3(x-4)+3x)-12=0



We calculate terms in parentheses: -(3(x-4)+3x), so:

3(x-4)+3x

We add all the numbers together, and all the variables

3x+3(x-4)

We multiply parentheses

3x+3x-12

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

6x-6x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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