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6(x-2)-3x=3(x-4)
We move all terms to the left:
6(x-2)-3x-(3(x-4))=0
We add all the numbers together, and all the variables
-3x+6(x-2)-(3(x-4))=0
We multiply parentheses
-3x+6x-(3(x-4))-12=0
We calculate terms in parentheses: -(3(x-4)), so:We add all the numbers together, and all the variables
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
3x-(3x-12)-12=0
We get rid of parentheses
3x-3x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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