6(x-2)-2x=2(x-10)+24

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Solution for 6(x-2)-2x=2(x-10)+24 equation: 



6(x-2)-2x=2(x-10)+24

We move all terms to the left:

6(x-2)-2x-(2(x-10)+24)=0

We add all the numbers together, and all the variables

-2x+6(x-2)-(2(x-10)+24)=0

We multiply parentheses

-2x+6x-(2(x-10)+24)-12=0



We calculate terms in parentheses: -(2(x-10)+24), so:

2(x-10)+24

We multiply parentheses

2x-20+24

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

4x-(2x+4)-12=0

We get rid of parentheses

4x-2x-4-12=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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