6(x-2)+7=2(x+4)+10

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Solution for 6(x-2)+7=2(x+4)+10 equation: 



6(x-2)+7=2(x+4)+10

We move all terms to the left:

6(x-2)+7-(2(x+4)+10)=0

We multiply parentheses

6x-(2(x+4)+10)-12+7=0



We calculate terms in parentheses: -(2(x+4)+10), so:

2(x+4)+10

We multiply parentheses

2x+8+10

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

6x-(2x+18)-5=0

We get rid of parentheses

6x-2x-18-5=0

We add all the numbers together, and all the variables

4x-23=0

We move all terms containing x to the left, all other terms to the right

4x=23

x=23/4

x=5+3/4

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