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6(x-2)+4=2(x-4)
We move all terms to the left:
6(x-2)+4-(2(x-4))=0
We multiply parentheses
6x-(2(x-4))-12+4=0
We calculate terms in parentheses: -(2(x-4)), so:We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
6x-(2x-8)-8=0
We get rid of parentheses
6x-2x+8-8=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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