6(x-2)+3(x+2)+2(x+3)=11

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Solution for 6(x-2)+3(x+2)+2(x+3)=11 equation:


6(x-2)+3(x+2)+2(x+3)=11

We simplify the equation to the form, which is simple to understand 
6(x-2)+3(x+2)+2(x+3)=11

Reorder the terms in parentheses
+(+6x-12)+3*(x+2)+2*(x+3)=11

Remove unnecessary parentheses
+6x-12+3+*(+x+2+)+2+*(+x+3+)=+11

Reorder the terms in parentheses
+6x-12+(+3x+6)+2*(x+3)=11

Remove unnecessary parentheses
+6x-12+3x+6+2+*(+x+3+)=+11

Reorder the terms in parentheses
+6x-12+3x+6+(+2x+6)=11

Remove unnecessary parentheses
+6x-12+3x+6+2x+6=+11

We move all terms containing x to the left and all other terms to the right. 
+6x+3x+2x=+11+12-6-6

We simplify left and right side of the equation. 
+11x=+11

We divide both sides of the equation by 11 to get x. 
x=1

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