6(x-2)+3(4-x)=5(x-1)+3

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Solution for 6(x-2)+3(4-x)=5(x-1)+3 equation: 



6(x-2)+3(4-x)=5(x-1)+3

We move all terms to the left:

6(x-2)+3(4-x)-(5(x-1)+3)=0

We add all the numbers together, and all the variables

6(x-2)+3(-1x+4)-(5(x-1)+3)=0

We multiply parentheses

6x-3x-(5(x-1)+3)-12+12=0



We calculate terms in parentheses: -(5(x-1)+3), so:

5(x-1)+3

We multiply parentheses

5x-5+3

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We add all the numbers together, and all the variables

3x-(5x-2)=0

We get rid of parentheses

3x-5x+2=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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