6(x-2)+2x=7(x+4)-38

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Solution for 6(x-2)+2x=7(x+4)-38 equation: 



6(x-2)+2x=7(x+4)-38

We move all terms to the left:

6(x-2)+2x-(7(x+4)-38)=0

We add all the numbers together, and all the variables

2x+6(x-2)-(7(x+4)-38)=0

We multiply parentheses

2x+6x-(7(x+4)-38)-12=0



We calculate terms in parentheses: -(7(x+4)-38), so:

7(x+4)-38

We multiply parentheses

7x+28-38

We add all the numbers together, and all the variables

7x-10

Back to the equation:

-(7x-10)



We add all the numbers together, and all the variables

8x-(7x-10)-12=0

We get rid of parentheses

8x-7x+10-12=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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