6(x-2)+2x-4=8(x+2)-8

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Solution for 6(x-2)+2x-4=8(x+2)-8 equation: 



6(x-2)+2x-4=8(x+2)-8

We move all terms to the left:

6(x-2)+2x-4-(8(x+2)-8)=0

We add all the numbers together, and all the variables

2x+6(x-2)-(8(x+2)-8)-4=0

We multiply parentheses

2x+6x-(8(x+2)-8)-12-4=0



We calculate terms in parentheses: -(8(x+2)-8), so:

8(x+2)-8

We multiply parentheses

8x+16-8

We add all the numbers together, and all the variables

8x+8

Back to the equation:

-(8x+8)



We add all the numbers together, and all the variables

8x-(8x+8)-16=0

We get rid of parentheses

8x-8x-8-16=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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