6(x-2)+21=4x+x+1

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Solution for 6(x-2)+21=4x+x+1 equation: 



6(x-2)+21=4x+x+1

We move all terms to the left:

6(x-2)+21-(4x+x+1)=0

We add all the numbers together, and all the variables

6(x-2)-(5x+1)+21=0

We multiply parentheses

6x-(5x+1)-12+21=0

We get rid of parentheses

6x-5x-1-12+21=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

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