6(x-1)=4(1+1/4x)+6+3x

Solution for 6(x-1)=4(1+1/4x)+6+3x equation:

6(x-1)=4(1+1/4x)+6+3x

We move all terms to the left:

6(x-1)-(4(1+1/4x)+6+3x)=0


Domain of the equation: 4x)+6+3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

6(x-1)-(4(1/4x+1)+6+3x)=0

We multiply parentheses

6x-(4(1/4x+1)+6+3x)-6=0

We multiply all the terms by the denominator


6x*4x+1)+6+3x)-(4(1-6*4x+1)+6+3x)=0

We add all the numbers together, and all the variables

6x*4x+1)+6+3x)-(4(-6*4x+2)+6+3x)=0

Wy multiply elements

24x^2+1)+6+3x)-(4(-24x+2)+6+3x)=0

We add all the numbers together, and all the variables

24x^2-24x+1)+6+3x)-(4(+2)+6+3x)=0

We add all the numbers together, and all the variables

24x^2-24x+1)+6+3x)-(42+6+3x)=0

We add all the numbers together, and all the variables

24x^2-24x+1)+6+3x)-(3x+48)=0