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6(x-1)=3(2x+2)
We move all terms to the left:
6(x-1)-(3(2x+2))=0
We multiply parentheses
6x-(3(2x+2))-6=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
6x-6x-6-6=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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