6(x-1)/10=3(x+3)/9

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Solution for 6(x-1)/10=3(x+3)/9 equation: 



6(x-1)/10=3(x+3)/9

We move all terms to the left:

6(x-1)/10-(3(x+3)/9)=0

We calculate fractions


6x/()+(-(3(x+3)*10)/()=0



We calculate terms in parentheses: +(-(3(x+3)*10)/(), so:

-(3(x+3)*10)/(

We multiply all the terms by the denominator


-(3(x+3)*10)



We calculate terms in parentheses: -(3(x+3)*10), so:

3(x+3)*10

We multiply parentheses

30x+90

Back to the equation:

-(30x+90)



We get rid of parentheses

-30x-90

Back to the equation:

+(-30x-90)



We get rid of parentheses

6x/()-30x-90=0

We multiply all the terms by the denominator


6x-30x*()-90*()=0

We add all the numbers together, and all the variables

6x-30x*()=0

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