6(x-1)+7=3(2x-5)+10

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Solution for 6(x-1)+7=3(2x-5)+10 equation: 


Simplifying
6(x + -1) + 7 = 3(2x + -5) + 10

Reorder the terms:
6(-1 + x) + 7 = 3(2x + -5) + 10
(-1 * 6 + x * 6) + 7 = 3(2x + -5) + 10
(-6 + 6x) + 7 = 3(2x + -5) + 10

Reorder the terms:
-6 + 7 + 6x = 3(2x + -5) + 10

Combine like terms: -6 + 7 = 1
1 + 6x = 3(2x + -5) + 10

Reorder the terms:
1 + 6x = 3(-5 + 2x) + 10
1 + 6x = (-5 * 3 + 2x * 3) + 10
1 + 6x = (-15 + 6x) + 10

Reorder the terms:
1 + 6x = -15 + 10 + 6x

Combine like terms: -15 + 10 = -5
1 + 6x = -5 + 6x

Add '-6x' to each side of the equation.
1 + 6x + -6x = -5 + 6x + -6x

Combine like terms: 6x + -6x = 0
1 + 0 = -5 + 6x + -6x
1 = -5 + 6x + -6x

Combine like terms: 6x + -6x = 0
1 = -5 + 0
1 = -5

Solving
1 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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