6(x-1)+2(x+4)=3(x+4)

Solution for 6(x-1)+2(x+4)=3(x+4) equation:

6(x-1)+2(x+4)=3(x+4)

We move all terms to the left:

6(x-1)+2(x+4)-(3(x+4))=0

We multiply parentheses

6x+2x-(3(x+4))-6+8=0


We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)


We add all the numbers together, and all the variables

8x-(3x+12)+2=0

We get rid of parentheses

8x-3x-12+2=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2