6(x-1)(x+1)+8=2

Solution for 6(x-1)(x+1)+8=2 equation:

Simplifying
6(x + -1)(x + 1) + 8 = 2

Reorder the terms:
6(-1 + x)(x + 1) + 8 = 2

Reorder the terms:
6(-1 + x)(1 + x) + 8 = 2

Multiply (-1 + x) * (1 + x)
6(-1(1 + x) + x(1 + x)) + 8 = 2
6((1 * -1 + x * -1) + x(1 + x)) + 8 = 2
6((-1 + -1x) + x(1 + x)) + 8 = 2
6(-1 + -1x + (1 * x + x * x)) + 8 = 2
6(-1 + -1x + (1x + x2)) + 8 = 2

Combine like terms: -1x + 1x = 0
6(-1 + 0 + x2) + 8 = 2
6(-1 + x2) + 8 = 2
(-1 * 6 + x2 * 6) + 8 = 2
(-6 + 6x2) + 8 = 2

Reorder the terms:
-6 + 8 + 6x2 = 2

Combine like terms: -6 + 8 = 2
2 + 6x2 = 2

Add '-2' to each side of the equation.
2 + -2 + 6x2 = 2 + -2

Combine like terms: 2 + -2 = 0
0 + 6x2 = 2 + -2
6x2 = 2 + -2

Combine like terms: 2 + -2 = 0
6x2 = 0

Solving
6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x2 = 0

Simplifying
x2 = 0

Take the square root of each side:
x = {0}