6(x+9)+x=2(x+3)-5

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Solution for 6(x+9)+x=2(x+3)-5 equation: 



6(x+9)+x=2(x+3)-5

We move all terms to the left:

6(x+9)+x-(2(x+3)-5)=0

We add all the numbers together, and all the variables

x+6(x+9)-(2(x+3)-5)=0

We multiply parentheses

x+6x-(2(x+3)-5)+54=0



We calculate terms in parentheses: -(2(x+3)-5), so:

2(x+3)-5

We multiply parentheses

2x+6-5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

7x-(2x+1)+54=0

We get rid of parentheses

7x-2x-1+54=0

We add all the numbers together, and all the variables

5x+53=0

We move all terms containing x to the left, all other terms to the right

5x=-53

x=-53/5

x=-10+3/5

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