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6(x+5)=3(x+1)
We move all terms to the left:
6(x+5)-(3(x+1))=0
We multiply parentheses
6x-(3(x+1))+30=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
6x-3x-3+30=0
We add all the numbers together, and all the variables
3x+27=0
We move all terms containing x to the left, all other terms to the right
3x=-27
x=-27/3
x=-9
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