6(x+5)+2=8(2x-5)+22+

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Solution for 6(x+5)+2=8(2x-5)+22+ equation: 



6(x+5)+2=8(2x-5)+22+

We move all terms to the left:

6(x+5)+2-(8(2x-5)+22+)=0

We multiply parentheses

6x-(8(2x-5)+22+)+30+2=0



We calculate terms in parentheses: -(8(2x-5)+22+), so:

8(2x-5)+22+

We add all the numbers together, and all the variables

8(2x-5)

We multiply parentheses

16x-40

Back to the equation:

-(16x-40)



We add all the numbers together, and all the variables

6x-(16x-40)+32=0

We get rid of parentheses

6x-16x+40+32=0

We add all the numbers together, and all the variables

-10x+72=0

We move all terms containing x to the left, all other terms to the right

-10x=-72

x=-72/-10

x=7+1/5

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