6(x+5)+11=35+4x

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Solution for 6(x+5)+11=35+4x equation: 



6(x+5)+11=35+4x

We move all terms to the left:

6(x+5)+11-(35+4x)=0

We add all the numbers together, and all the variables

6(x+5)-(4x+35)+11=0

We multiply parentheses

6x-(4x+35)+30+11=0

We get rid of parentheses

6x-4x-35+30+11=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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