6(x+4)+3x-2=58

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Solution for 6(x+4)+3x-2=58 equation: 



6(x+4)+3x-2=58

We move all terms to the left:

6(x+4)+3x-2-(58)=0

We add all the numbers together, and all the variables

3x+6(x+4)-60=0

We multiply parentheses

3x+6x+24-60=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4

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