6(x+3)=98+2x

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Solution for 6(x+3)=98+2x equation:



6(x+3)=98+2x
We move all terms to the left:
6(x+3)-(98+2x)=0
We add all the numbers together, and all the variables
6(x+3)-(2x+98)=0
We multiply parentheses
6x-(2x+98)+18=0
We get rid of parentheses
6x-2x-98+18=0
We add all the numbers together, and all the variables
4x-80=0
We move all terms containing x to the left, all other terms to the right
4x=80
x=80/4
x=20

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