6(x+3)=7(4x-5)

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Solution for 6(x+3)=7(4x-5) equation: 



6(x+3)=7(4x-5)

We move all terms to the left:

6(x+3)-(7(4x-5))=0

We multiply parentheses

6x-(7(4x-5))+18=0



We calculate terms in parentheses: -(7(4x-5)), so:

7(4x-5)

We multiply parentheses

28x-35

Back to the equation:

-(28x-35)



We get rid of parentheses

6x-28x+35+18=0

We add all the numbers together, and all the variables

-22x+53=0

We move all terms containing x to the left, all other terms to the right

-22x=-53

x=-53/-22

x=2+9/22

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