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6(x+3)=4-2(x-9)
We move all terms to the left:
6(x+3)-(4-2(x-9))=0
We multiply parentheses
6x-(4-2(x-9))+18=0
We calculate terms in parentheses: -(4-2(x-9)), so:We get rid of parentheses
4-2(x-9)
determiningTheFunctionDomain -2(x-9)+4
We multiply parentheses
-2x+18+4
We add all the numbers together, and all the variables
-2x+22
Back to the equation:
-(-2x+22)
6x+2x-22+18=0
We add all the numbers together, and all the variables
8x-4=0
We move all terms containing x to the left, all other terms to the right
8x=4
x=4/8
x=1/2
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