6(x+3)=4(1+x)

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Solution for 6(x+3)=4(1+x) equation: 



6(x+3)=4(1+x)

We move all terms to the left:

6(x+3)-(4(1+x))=0

We add all the numbers together, and all the variables

6(x+3)-(4(x+1))=0

We multiply parentheses

6x-(4(x+1))+18=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

6x-4x-4+18=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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