6(x+3)=3(2x-3)+27

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Solution for 6(x+3)=3(2x-3)+27 equation: 



6(x+3)=3(2x-3)+27

We move all terms to the left:

6(x+3)-(3(2x-3)+27)=0

We multiply parentheses

6x-(3(2x-3)+27)+18=0



We calculate terms in parentheses: -(3(2x-3)+27), so:

3(2x-3)+27

We multiply parentheses

6x-9+27

We add all the numbers together, and all the variables

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

6x-6x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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