6(x+3)2x=26

Solution for 6(x+3)2x=26 equation:

6(x+3)2x=26

We move all terms to the left:

6(x+3)2x-(26)=0

We multiply parentheses

12x^2+36x-26=0

a = 12; b = 36; c = -26;
Δ = b2-4ac
Δ = 362-4·12·(-26)
Δ = 2544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2544}=\sqrt{16*159}=\sqrt{16}*\sqrt{159}=4\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{159}}{2*12}=\frac{-36-4\sqrt{159}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{159}}{2*12}=\frac{-36+4\sqrt{159}}{24}
$