6(x+3)-4=2(7+3x)

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Solution for 6(x+3)-4=2(7+3x) equation: 



6(x+3)-4=2(7+3x)

We move all terms to the left:

6(x+3)-4-(2(7+3x))=0

We add all the numbers together, and all the variables

6(x+3)-(2(3x+7))-4=0

We multiply parentheses

6x-(2(3x+7))+18-4=0



We calculate terms in parentheses: -(2(3x+7)), so:

2(3x+7)

We multiply parentheses

6x+14

Back to the equation:

-(6x+14)



We add all the numbers together, and all the variables

6x-(6x+14)+14=0

We get rid of parentheses

6x-6x-14+14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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