6(x+3)-4=-4(x+3)+6

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Solution for 6(x+3)-4=-4(x+3)+6 equation: 



6(x+3)-4=-4(x+3)+6

We move all terms to the left:

6(x+3)-4-(-4(x+3)+6)=0

We multiply parentheses

6x-(-4(x+3)+6)+18-4=0



We calculate terms in parentheses: -(-4(x+3)+6), so:

-4(x+3)+6

We multiply parentheses

-4x-12+6

We add all the numbers together, and all the variables

-4x-6

Back to the equation:

-(-4x-6)



We add all the numbers together, and all the variables

6x-(-4x-6)+14=0

We get rid of parentheses

6x+4x+6+14=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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