6(x+3)-2(x-4)=10(x-1)

Solution for 6(x+3)-2(x-4)=10(x-1) equation:

6(x+3)-2(x-4)=10(x-1)

We move all terms to the left:

6(x+3)-2(x-4)-(10(x-1))=0

We multiply parentheses

6x-2x-(10(x-1))+18+8=0


We calculate terms in parentheses: -(10(x-1)), so:

10(x-1)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)


We add all the numbers together, and all the variables

4x-(10x-10)+26=0

We get rid of parentheses

4x-10x+10+26=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6