6(x+3)+x=3(x+5)+7

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Solution for 6(x+3)+x=3(x+5)+7 equation: 



6(x+3)+x=3(x+5)+7

We move all terms to the left:

6(x+3)+x-(3(x+5)+7)=0

We add all the numbers together, and all the variables

x+6(x+3)-(3(x+5)+7)=0

We multiply parentheses

x+6x-(3(x+5)+7)+18=0



We calculate terms in parentheses: -(3(x+5)+7), so:

3(x+5)+7

We multiply parentheses

3x+15+7

We add all the numbers together, and all the variables

3x+22

Back to the equation:

-(3x+22)



We add all the numbers together, and all the variables

7x-(3x+22)+18=0

We get rid of parentheses

7x-3x-22+18=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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