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6(x+3)+4=8(x-4)-11
We move all terms to the left:
6(x+3)+4-(8(x-4)-11)=0
We multiply parentheses
6x-(8(x-4)-11)+18+4=0
We calculate terms in parentheses: -(8(x-4)-11), so:We add all the numbers together, and all the variables
8(x-4)-11
We multiply parentheses
8x-32-11
We add all the numbers together, and all the variables
8x-43
Back to the equation:
-(8x-43)
6x-(8x-43)+22=0
We get rid of parentheses
6x-8x+43+22=0
We add all the numbers together, and all the variables
-2x+65=0
We move all terms containing x to the left, all other terms to the right
-2x=-65
x=-65/-2
x=32+1/2
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