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6(x+3)+1=-(1-2x)
We move all terms to the left:
6(x+3)+1-(-(1-2x))=0
We add all the numbers together, and all the variables
6(x+3)-(-(-2x+1))+1=0
We multiply parentheses
6x-(-(-2x+1))+18+1=0
We calculate terms in parentheses: -(-(-2x+1)), so:We add all the numbers together, and all the variables
-(-2x+1)
We get rid of parentheses
2x-1
Back to the equation:
-(2x-1)
6x-(2x-1)+19=0
We get rid of parentheses
6x-2x+1+19=0
We add all the numbers together, and all the variables
4x+20=0
We move all terms containing x to the left, all other terms to the right
4x=-20
x=-20/4
x=-5
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